DNA profiling 2

DNA profiling 2

Describe the limitations of DNA profiling in relation to the two uses of DNA profiling.

Paternity Test:

The more people tested the lower the statistical probability.

Criminal Investigation:

New profiling technologies can give incorrect results due to cross-contamination of samples.

DNA evidence is easily planted at a crime scene

Other limitations

End of Genetics paper 2

a)     Calculate the difference in consumption of the 6% alcohol solution between the

I)               NPY -/- and NPY +/+ : 3 grams per kilogram weight are consumed per day

II)              NPY – EX and NPY +/+ 2 grams per kilogram weight are consumed per day

b)     NPY -/- consumes more alcohol than NPY +/+ but NPY-EX consumes less than NPY +/+. NPY -/- also consumes more alcohol than NPY-EX. The consumption levels off at a higher concentration for NPY -/- than it does for NPY-EX.

c)     The relationship between NPY levels and alcohol consumption is inversely related.

d)     NPY -/- can regain the reflex fastest, whereas NPY-EX takes the longest. This is because NPY-EX is affected more by alcohol than NPY-/- is.

e)     The hypothesis is not fully supported. There is a small difference in blood levels at 1 hour and 3 hours.

f)      NPY-EX is more affected to alcohol and thus doesn’t prefer it. Unlike NPY -/- which prefers alcohol because it is less sensitive to alcohol and therefore has more of it.

g)      

a.     Homozygous means that there are two identical alleles of the same gene

b.     It has normal levels of NPY

c.      

	NPY+	NPY +
NPY -	NPY +/-	NPY +/-
NPY -	NPY +/-	NPY +/-

100%

1.

a) There is a higher percentage of lectin in all GNA varieties in comparison to Con A varieties by about ten fold.

b) Con A 4 because it has the highest percentage of Aphid and Nematode control.

c) It seems that the higher the lectin content the better aphid control however there does not seem to be a relationship with Nematode control.

d) (5500-3800/5000) x 100 = 34%

e) There is a greater effect of the GM potatoes on protozoa because the percentage difference of the mean mass of protozoa is greater than the nematodes. This is the case for both GNA 2#28 and Con A 31. For example, the percentage difference in mass was 63% and 51% for the flagellates and amoebae but for the nematodes it was only 34%.